It is a known fact that most US dollar bill contain cocaine. According to the Argonne National Laboratory study "the average contamination was 16 micrograms (or 0.000016 grams.)" carrying more than 5 grams of cocaine will land you in jail.
Therefore you would have to carry 312,500 bills in order to be charged for possession of coke. Or 312.5 kg or 688.94 pounds of bills!
The math:
1 Bill = 0.000016 grams
x Bills = 5.00000 grams
1. Set up as two fractions (the bills and the grams)
1/x and 0.000016/5.00000
2. Cross multiply
5 = 0.000016x
3. Solve for x
x = 312,500 one dollar bills
For the weight. 1 bill = 1 gram. So 312,500 bills would weigh 312.5 kg or 688.94 pounds
